J.R. S. answered 04/21/20
Ph.D. University Professor with 10+ years Tutoring Experience
For this, you can use V1M1 = V2M2
(35.0 ml)(1.75 M) = (500 ml)(x M)
x = 0.1225 M = 0.123 M (3 significant figures)
Rafael V.
asked 04/21/20If you dilute 35.0 mL of 1.75 M hydrochloric acid to 600. mL, what is the molar concentration of the dilute acid?
Molar concentration=____M
J.R. S. answered 04/21/20
Ph.D. University Professor with 10+ years Tutoring Experience
For this, you can use V1M1 = V2M2
(35.0 ml)(1.75 M) = (500 ml)(x M)
x = 0.1225 M = 0.123 M (3 significant figures)
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