Help with chemistry

Question

The temperature of a sample of aluminum increased by 22.0 C when 269 J of heat was applied.

lead 0.128

silver 0.235

copper 0.385

iron 0.449

aluminum 0.903

What is the mass of the sample?

Answer 1

q = mC∆T

q = heat = 269 J

m = mass = ?

C = specific heat for aluminum = 0.903 J/g/degree (you didn't give the units for C, but this is what it is)

∆T = change in temperature = 22 degrees

Solving the equation for m, we have...

m = q / C∆T

m = 269 J / (0.903 J/g-degree)(22 degrees)

m = 13.5 g of aluminum