J.R. S. answered 04/17/20
Ph.D. University Professor with 10+ years Tutoring Experience
q = mC∆T
q = heat = 6500 J
m = mass = 300 g
C = specific heat = 0.390 J/g/degree
∆T = change in temperature = ?
6500 J = (300 g)(0.390 J/g/deg)(∆T)
∆T = 600/(300)(0.390)
∆T = 55.6 degrees