for chem I need help in a galvanic question

Question

consider a voltaic cell made up of copper and sodium half cells. Write the half reactions, the balanced overall reaction, and determine the cell potential under standard conditions. Spontaneous or nonspontaneous ?

Answer 1

Cu²⁺ + 2e- ===> Cu(s) Eº = -0.337 V

Na⁺ + e- ===> Na(s) Eº = -2.71 V

Since reduction potential for Cu²⁺ is greater than that for Na⁺, Cu²⁺ will be reduced at the cathode and Na will be oxidized at the anode.

Half reactions:

Cu²⁺ + 2e- ===> Cu(s) ... reduction (cathode)

Na(s) ===> Na⁺ + e- ... oxidation (anode)

Balanced overall reaction:

Cu²⁺ + 2Na(s) ==> Cu(s) + 2Na⁺

Cell Potential:

Eºcell = Eºcathode - Eºanode = -0.337 - (-2.71)

Eºcell = 2.37 V (spontaneous because it is positive)