Chemistry math help

Question

What concentration of CI- results when 991mL of  0.763M LiCl is mixed with 717mL of 0.693 M MgCl2

Answer 1

moles of Cl- from LiCl. LiCl ==> Li⁺ + Cl^-

991 ml x 1 L/1000 ml x 0.763 moles/L = 0.7561 moles Cl^-

moles Cl^- from MgCl₂. MgCl₂ ==> Mg²⁺ + 2Cl^-

717 ml x 1 L/1000 ml x 0.693 mol/L x 2 mol Cl-/mol MgCl₂ = 0.9938 moles Cl^-

Total volume = 991 ml + 717 ml = 1708 ml = 1.708 L

Total moles Cl^- = 0.7561 + 0.9938 = 1.75 moles

[Cl^-] = moles Cl-/liter

[Cl^-] = 1.75 mol/1.708 L

[Cl^-] = 1.02 M (3 sig. figs.