Percent Yield- Chemistry HW

Question

An excess of sodium carbonate,  in solution is added to a solution containing  16.35 g CaCl2 .After performing the experiment, 13.39 g  of calcium carbonate,  is produced. Calculate the percent yield of this reaction

Answer 1

Na₂CO₃ + CaCl₂ ==> CaCO₃(s) + 2NaCl ... balanced equation

moles CaCl₂ used = 16.35 g x 1 mol/110.98 g = 0.1473 moles

Theoretical yield of CaCO₃ = 0.1473 mol CaCl₂ x 1 mol CaCO₃/mol CaCl₂ x 100.09 g/mol = 14.75 g

Percent yield = actual yield/theoretical yield (x100%) = 13.39 g/14.75 g (x100%) = 90.78%