How many mL of a 0.10 M NaOH solution are needed to neutralize 25.0 mL of 0.200 M H2SO4 solution?

Answer 1

The reaction is 2NaOH + H2SO4 ==> 2H2O + Na2SO4

Note: it takes TWO moles NaOH for each ONE mole H2SO4

25.0 ml H2SO4 x 1 L/1000 ml x 0.200 moles/L = 0.005 moles H2SO4 present

moles NaOH required = 0.005 mol H2SO4 x 2 mol NaOH/mol H2SO4 = 0.01 mole NaOH required

Now to find the volume of 0.1 M NaOH needed to provide 0.01 moles NaOH:

(0.1 mol/L) (x L) = 0.01 moles

x = 0.1 L = 100 mls of 0.10 M NaOH