J.R. S. answered 04/16/20
Ph.D. University Professor with 10+ years Tutoring Experience
You need to learn the following relationships, and then you can do any and all of these problems:
- [H+][OH-] = Kw = 1x10-14
- pH = -log [H+] and pOH = -log [OH-]
- pH + pOH = 14
Determine the [OH^-], pH, and pOH of a solution with a [H^+] of 9.4 x 10^-7 M at 25 °C.
[OH-] = Kw/[H+] = 1x10-14/9.4x10-7 = 1.06x10-8 M
pH = 14 - pOH and pOH = -log [OH-] = -log 1.06x10-8 = 7.97. pH = 14 - 7.97 = 6.03 = pH
pOH = -log [OH-] = 7.97. pOH also = 14 - pH = 14 - 6.03 = 7.97
You can do the rest using the above relationships. Practice, practice, practice.