The gas left in a used aerosol can is at a pressure of 2.3 atm at 25.7°C. If this can is thrown into a fire, what is the internal pressure of the gas in atm when its temperature reaches 132.7°C?

Answer 1

P1 = 2.3 atm

T1 = 25.7ºC + 273 = 298.7K

P2 = ?

T2 = 132.7ºC + 273 = 405.7

At constant volume...

P1/T1 = P2/T2 and solving for P2, we have...

P2 = P1T2/T1

P2 = (2.3 atm)(405.7K)/298.7K

P2 = 3.1 atm