Gas Law Chemistry

Question

A weather balloon is filled with helium that occupies a volume of 6.32  10⁴ L at 0.995 atm and 32.0°C. After it is released, it rises to a location where the pressure is 0.720 atm and the temperature is -11.3°C. What is the volume of the balloon at that new location?

Answer 1

P1 = 0.995 atm

V1 = 6.32x104 L

T1 = 32.0º + 273 = 305K

P2 = 0.720 atm

V2 = ?

T2 = -11.3 + 273 = 261.7K

Combined Gas Law:

P1V1/T1 = P2V2/T2 and solving for V2...

V2 = P1V1T2/P2T1

Plug in the above values and solve for V2 (units will be in liters)