Chemistry Combined Gas Laws

Question

Consider 4.80 L of a gas at 365 mmHg and 20.C  . If the container is compressed to 3.00 L and the temperature is increased to 38 C , what is the new pressure, , inside the container? Assume no change in the amount of gas inside the cylinder.

Answer 1

V1 = 4.80 L

P1 = 365 mm Hg

T1 = 20ºC + 273 = 293K

V2 = 3.00 L

T2 = 38ºC + 273 = 311K

P2 = ?

Combined Gas Law:

P1V1/T1 = P2V2/T2

Rearranging to solve for P2, we have

P2 = P1V1T2 / T1V2

Plug in the values and solve