What is the mass of a sample of zinc that absorbed 198.5 joules of energy when heated from an initial temperature of 234°C to 439°C? The specific heat of aluminum is .388J/g°C.

Answer 1

q = mC∆T

q = heat =198.5 J

m = mass = ?

C = specific heat = 0.388 J/g/degree

∆T = change in temperature = 439 - 234 = 205 degrees

198.5 J = (m)(0.388 J/g/deg)(205 deg)

m = 198.5 J/0.388 J/g/deg x 205 deg

m = 2.496 g = 2.50 g Zn