J.R. S. answered 04/14/20
Ph.D. University Professor with 10+ years Tutoring Experience
P1 = 1.00 atm
V1 = 350. L
P2 = ?
V2 = 2.00 L
P1V1 = P2V2
(1.00 atm)(350. L) = (P2)(2.00 L)
P2 = 175 atm
Breanna A.
asked 04/13/20Once you’ve identified the initial and final conditions, you’re ready to solve for the unknown quantity in your problem. Boyle’s Law expresses the pressure-volume relationship as P1V1=P2V2 , so you will need to solve this equation for the unknown quantity and then plug in your known values to calculate the unknown.
What pressure would it take to compress 350. L of helium gas initially at 1.00 atm into a 2.00 L tank at constant temperature?
J.R. S. answered 04/14/20
Ph.D. University Professor with 10+ years Tutoring Experience
P1 = 1.00 atm
V1 = 350. L
P2 = ?
V2 = 2.00 L
P1V1 = P2V2
(1.00 atm)(350. L) = (P2)(2.00 L)
P2 = 175 atm
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