Here are two ways of solving the problem.
In similar triangles, the ratio of their areas equals the square of the ratio of their sides.
The ratio of their perimeters is 1:3 so the ratio of their sides and their altitudes will also be in the ratio of 1:3.
That given, the ratios of the areas is 1^2/3^2=1/9. (ratio of their sides: a/b, ratio of their areas: a^2/b^2)
Therefore we have 1/9=A/27 where A=area of the smaller triangle
cross multiply
1*27=9*A
27=9A
A=27/9
A=3 square feet is the area of the smaller triangle
Suppose that you did not know this.
Let one triangle have sides a, b and c.
Let the other triangle be 3a, 3b and 3c.
Let h=altitude of the smaller triangle.
3h=altitude of the larger triangle
let b and 3b be the bases of the triangles
A=(1/2)(b)(h) is the area of the smaller triangle.
A=(1/2)(3b)(3h) is the area of the larger triangle.
27=(1/2)(9bh)
27=4.5bh
bh=27/4.5
bh=6
substitute this into the first area formula for the smaller triangle
A=(1/2)(6)
A=3 square feet is the area of the smaller triangle again