J.R. S. answered 04/13/20
Ph.D. University Professor with 10+ years Tutoring Experience
w = -P∆V
w = work
P = pressure = 1.79 atm
∆V = change in volume = 2.87 L - 8.48 L = - -5.61 L
w = -(1.79 atm x -5.61 L) = +10 Latm
converting to J we have 10 Latm x 101.325 J/Latm = +1013 J of work done ON THE SYSTEM
∆U = q + w = 350 J + 1013 J = 1023 J