J.R. S. answered 04/13/20
Ph.D. University Professor with 10+ years Tutoring Experience
2H2 + 2F2 ===> 4HF ∆H = -1093.2 kJ
2H2O ===> 2H2 + O2 ∆H = +571.6 kJ
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2H2 + 2F2 + 2H2O ===> 4HF + 2H2 + O2
2F2 + 2H2O ===> 4HF + O2
∆H = -1093.2 + 571.6
∆H = -521.6 kJ