Given that Eored of ozone is 2.07 V, calculate Eored of MO2.

Question

Consider the reaction between ozone and a metal cation, M²⁺, to form the metal oxide, MO₂, and dioxygen:

O₃ + M²⁺(aq) + H₂O(l) →O₂(g) + MO₂(s) + 2 H⁺

for which E^o_cell = 0.3.

Given that E^o_red of ozone is 2.07 V, calculate E^o_red of MO₂

the answer is: 1.77

please show steps so I can follow along, thank you!

Answer 1

Eºcell = reduction potential of reduction reaction - reduction potential of oxidation reaction

Put another way, Eºcell = Eºcathode - Eºanode

0.3 = 2.07 - X

-1.77 = - X

X = Eº of MO₂ = +1.77