Stock solutions of nitric acid have concentration of 16.0 M. What volume of stock solution is needed to prepare 2.00 L of 2.00 M solution of nitric acid by dilution with water?

Answer 1

M₁V₁=M₂V₂

V₁ = M₂V₂/M₁ = 2M x 2L/16M = .25L nitric acid

Answer 2

M1V1 = M2V2

(x L)(16.0 M) = (2 L)(2.00 M)

x = 0.25 L = 250 mls of the stock solution is needed