An experiment requires 0.274 g of hydrobromic acid. Calculate the volume of 0.754 mol/L hydrobromic acid solution that can be used in the experiment.

Answer 1

0.754 mol HBr/L x 80.91 g HBr/mol HBr = 61.00 g/L HBr solution

(x L)(61.00 g/L) = 0.274 g

x = 0.00449 L = 4.49 mls needed

Answer 2

MW HBr: 80.92

.274gHBr x mol HBr/80.92g x L HBr/mo HBr = .00339 L HBr