J.R. S. answered 04/09/20
Ph.D. University Professor with 10+ years Tutoring Experience
Na is going from zero oxidation to 1+, so it is being oxidized.
Au is going from 3+ oxidation to zero, so it is being reduced.
Na ===> Na+ + 1e- ... oxidation 1/2 reaction
Au3+ + 3e- ==> Au ... reduction 1/2 reaction
We must multiply the oxidation reaction by 3 to equalize the number of electrons, so we have...
3Na ==> 3Na+ + 3e- and combining this with the reduction reaction we have...
3Na + Au3+ ==> 3Na+ + Au ... OVERAL REACTION