J.R. S. answered • 04/09/20
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O2 + 4Na ==> 2Na2O
Both oxygen and sodium on the left side of the reaction have oxidation numbers of zero (elements)
On the right side, oxygen has an oxidation number of 2- so it has been reduced.
On the right side, sodium has an oxidation number of 1+ so it has been oxidized.
Reduction half reaction:
O2 + 4e- ===> 2O2-
Oxidation half reaction:
4Na ==> 4Na+ + 4e-
J.R. S.
tutor
Hmm...Looks like the reaction is 4Na + O2 => 2Na2O and the half reactions would add up to that. Not sure about the software and how they want you to enter the answer. Unless we are missing something simple, this seems correct. I'll continue to think about it, and if I come up with anything, I'll comment back.
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04/09/20
J W.
Hi ! thank you for your help, but that is the answer that I put before and the software is still saying that it is wrong.04/09/20