J.R. S. answered 04/09/20
Ph.D. University Professor with 10+ years Tutoring Experience
q = heat = mC∆T
m = mass = 2.23 kg x 1000 g/kg = 2230 g
C = specific heat = 1.75 J/gºC
∆T = change in temperature = 191 - 23 = 168ºC
q = (2230 g)( 1.75 J/g/ºC)(165ºC)q = 655,620 J = 656,000 J (to 3 significant figures)