How many liters of H2 gas at STP can be produced by the reaction of 4.60 g of Na and excess water, according to the following equation? Mole ratio first. 2Na(s) + 2H2O(l) → H2(g) + 2NaOH(aq)

Question

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Answer 1

2Na(s) + 2H₂O(l) ==> H₂(g) + 2NaOH(aq)

Mole ratio is 2 Na to 1 H₂

4.60 g Na x 1 mol Na/23 g x 1 mol H2/2 mol Na x 22.4 L/mol = 2.24 L H₂