J.R. S. answered 04/08/20
Ph.D. University Professor with 10+ years Tutoring Experience
Ag2CO3(s) <==> 2Ag+(aq) + CO32-(aq)
Ksp = [Ag+]2[CO32-]
0.035 g Ag2CO3 x 1 mol/276 g = 1.27x10-4 moles in 1 L = 1.27x10-4 M = molar solubility
Ksp = [1.27x10-4]2[1.27x10-4]
Ksp = 2.05x10-12