Leon M.

asked • 04/07/20

what are the coordinates of point c on the directed segment from A(0,3) to B(-11,-18) that partitions the segment such that AC:CB is 5:3?

what are the coordinates of point c on the directed segment from A(0,3) to B(-11,-18) that partitions the segment such that AC:CB is 5:3?

choices

(-3.9,-7.1)

(-8.9,-8.1)

(-6.9,-10.1)

(-2.9,-14.1)

1 Expert Answer

By:

Sindhuja R. answered • 04/07/20

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Leon M.

i got -2.9, -14.1)
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04/08/20

Sindhuja R.

No, the answer i got is : (-6.9, -10.1). I have to mention a point here : If the point partitions the line segment internally then, the formula is : ( (m x2 + n x1) / (m+n) , (m y2 + n y1) / (m+n) ). If the point partitions the line segment externally then, the formula is : ( (m x2 - n x1) / (m-n) , (m y2 - n y1) / (m-n) ).
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04/08/20

Sindhuja R.

This is according to the formula: ( (m x2 + n x1) / (m+n) , (m y2 + n y1) / (m+n) ). => ( [ (5) (-11) + (3) (0) ] / 8) , [ (5) (-18) + (3) (3) ] / 8) => (-55/8 , (- 90+9) / 8 ) => (-55/8 , -81/8 ) => ( - 6.875, -10.1 )
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04/08/20

Leon M.

ok i see now i will write this formula down thank you so much
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04/08/20

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