Manan G.

asked • 04/07/20

# First-degree trigonometric equations help

In these questions, find, to the nearest degree, the positive acute angle(s) that satisfy the equation.

1) tan^2x - 4tanx + 3 = 0

2) tan^2x - 2tanx = 3

3) 6sin^2x - 5sinx + 1 = 0

## 2 Answers By Expert Tutors

By: Kathy Z. answered • 04/07/20

Tutor
4.9 (616)

Easy to understand Math and SAT preparation

Manan G.

Thank you very much. The steps are much clearer and I understand the question.
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04/08/20

Sindhuja R. answered • 04/07/20

Tutor
New to Wyzant

Experienced Tutor specializing in Geometry

Sindhuja R.

tanx=3 => tan inverse (3) = 71.56 , => x=71.56. (you could use scientific calculator to find tan inverse of 3 value) I have only given integer values earlier. So, the total range of values also include, tanx = 1 (45 degrees (1st Quadrant), 225 degrees (3rd Quadrant)) and tanx=3 (71.56 degrees (1st Quadrant), 251.56 degrees (3rd Quadrant)) )
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04/07/20

Sindhuja R.

Since the tan value generally is positive in 1st and 3rd quadrants and in this case 1 and 3 are positives. So, we find x value for both the quadrants.
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04/07/20

Sindhuja R.

If you want any basics or concepts of trigonometry, i could conduct a class for you as per your requirement.
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04/07/20

Manan G.

Thank you very much. I get it now.
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04/08/20

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