How many mL of 0.300 M NaF would be required to make a 0.0400 M solution of NaF when diluted to 250.0 mL with water?

Answer 1

Dilution problem:

M1V1 = M2V2

M1 = molarity of initial solution = 0.300 M

V1 = volume of initial solution = ?

M2 = molarity of final solution = 0.0400 M

V2 = volume of final solution = 250.0 ml

(0.300)(x ml) = (0.0400)(250.0 ml)

x = 33.33 mls = 33.3 mls (3 sig. figs.)