Mean = 50
Standard Deviation = 17
X = 52
n = 125
P(X>52) = (52-50)/(17/√125) = 2/1.52 = 1.32 (Use the z-score from whatever statistics textbook you have)
P(z>1.32) = 1 - P(z≤1.32) = 1 - 0.9066 = 0.0934
Aubyn H.
asked 04/07/20a sample size of 125 will be drawn from a population with mean 50 and standard deviation 17. the probability that x will be greater than 52 is
Mean = 50
Standard Deviation = 17
X = 52
n = 125
P(X>52) = (52-50)/(17/√125) = 2/1.52 = 1.32 (Use the z-score from whatever statistics textbook you have)
P(z>1.32) = 1 - P(z≤1.32) = 1 - 0.9066 = 0.0934
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