If 0.357 mol N2 has a volume of 9.2 L at some temperature and pressure, what volume would 0.845 mol N2 have at the same temperature and pressure?

Answer 1

From the ideal gas law, PV = nRT you see that when the volume (V) and the temperature (T) are constant, you essentially have P ∝ nR and R is also constant so P ∝ n, i.e. pressure is proportional to moles.

0.357 moles /9.2 L = 0.845 moles/x L

x = 21.8 L