Eunjin L.

asked • 04/06/20

balance these reactions and identify the type

Pb(OH)2 + HCl ----> H2O + PbCl2

Na + H2O -------> NaOH + H2

FeCl3 + NaOH ----> Fe(OH)3 + NaCl



Can you help me figure out how to balance these reactions and how to identify them? I have a hard time understanding! Thanks!

Wasiu L.

tutor
I Really can't help you with balancing. I would just say that you should use coefficients to make sure that every single element has the same number on either side. As for the types of reaction, the ones you have posted look like displacement reactions. You just have to determine if it's single displacement or double displacement.
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04/06/20

1 Expert Answer

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J.R. S. answered • 04/06/20

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Pb(OH)2 + HCl ----> H2O + PbCl2

Notice how you have something of the form AB + CD as reactants. This signals a double displacement, where partners are switched. So Pb goes with Cl and OH goes with H. You end up with PbCl and HOH, but that's not balanced. So in summary you have Pb(OH)2 + 2HCl ----> 2H2O + PbCl2


Na + H2O -------> NaOH + H2

Here you have something of the form A + BC and you can look at H2O as H-OH, where H is B and OH is C. This signals a single displacement, where A displaces B. So, you have Na + H2O ==> NaOH + H2 but this isn't balance. Balanced you have 2Na + 2H2O => 2NaOH + H2


FeCl3 + NaOH ----> Fe(OH)3 + NaCl

This is just like the first one. You have AB + CD signaling double displacement. Fe switches with OH leaving Na and Cl to hook up. So, after balancing you have FeCl3 + 3NaOH ----> Fe(OH)3 + 3NaCl

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