Chemistry 60 HW Help

Question

A  sample of  was added to  of  and mixed in water. A  yield of  was obtained.

Calculate the percent yield of 

Answer 1

CaCl₂(aq) + K₂CO₃(aq) ==> CaCO₃(s) + 2KCl(aq) ... balanced equation

(1). Find the limiting reactant:

14.571 g CaCl₂ x 1 mol CaCl₂/110.98g = 0.1313 moles

12.374 g K₂CO₃ x 1 mol K₂CO₃/138.21 g = 0.08953 moles <== Limiting reactant

(2). Find the theoretical yield of CaCO₃(s) using the moles of limiting reactant:

0.08953 mol K₂CO₃ x 1 mol CaCO₃/mol K₂CO₃ x 100.09 g CaCO₃/mol = 8.961 g CaCO₃

(3). Calculate percent yield:

% yield = actual yield/theoretical yield (x100%) = 3.582 g/8.961 g (x100%) = 39.97% yield