Solve triangle ABC. b=9, c=7, gamma = 48 degrees.

Question

I am confused someone please help

Answer 1

This looks like a law of codinrs problem.

c^2=a^2+b^2-2abcos(C)

Let c be the side facing 48 degrees.

Then c^2=9^2+7^2 -2*9*7*cos(48)

c^2=87.844

Take square root of both sides.

c=9.37

Answer 2

I assume you are looking for the length of side "a" ?

Use the Law of Cosines.

a^2=b^2+c^2-2bccosA

a^2=9^2+7^2-2*9*7*cos48°

a^2=81+49-126*0.66913060635

a^2=130-84.4310456

a^2=45.689544

a=√45.689544

a=6.7594