How much energy is required to raise the temperature of 18.6 grams of water from 15°C to 134°C?

Answer 1

heat = mass x specific heat x change in temperature

q = mC∆T

q = ?

m = 18.6 g

C = 4.184 J/g/ºC (specific heat for water)

∆T = 134 - 15 = 119º

q = (18.6 g)(4.184 J/g/ºC)(119ºC)

q = 9,261 J = 9.26 kJ