How many grams of sodium hydroxide are present in 247.0 mL of a 0.400 M NaOH solution?

Question

How many grams of sodium hydroxide are present in  of a   solution?

Answer 1

M = molarity = moles/liter

0.400 M = 0.400 moles NaOH/liter of solution

247.0 mls x 1 L/1000 mls = 0.2470 liters

0.400 mol/L x 0.2470 L = 0.0988 moles NaOH

molar mass NaOH = 39.997 g/mol

0.0988 moles NaOH x 39.997 g/mole = 3.95 g NaOH (3 significant figuires)