J.R. S. answered 04/05/20
Ph.D. University Professor with 10+ years Tutoring Experience
∆Gº = - RT ln K
∆Gº = - (0.008314)(589) ln 4.67x1028
∆Gº = - 4.897 x 66.0
∆Gº = -323 kJ
Oscar A.
asked 04/04/20At a certain temperature, 589 K, Kp for the reaction,
2 SO2(g) + O2(g) <=> 2 SO3(g) is 4.67 x 1028.
Calculate the value of ΔGo in kJ for the reaction at 589 K.
The correct answer is -323
J.R. S. answered 04/05/20
Ph.D. University Professor with 10+ years Tutoring Experience
∆Gº = - RT ln K
∆Gº = - (0.008314)(589) ln 4.67x1028
∆Gº = - 4.897 x 66.0
∆Gº = -323 kJ
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