Calculate the value of ln K for the reaction at this temperature to one decimal place.

Question

At 555 K, ΔG^o equals 139 kJ for the reaction, Br₂(g) <=> 2 Br(g) 

Calculate the value of ln K for the reaction at this temperature to one decimal place.

The answer is -30.1

Answer 1

ln K = -∆Gº/RT

ln K = -139 kJ/(0.008314 kJ/molK)(555K)

ln K = -139/4.61

ln K = -30.2