J.R. S. answered 04/05/20
Ph.D. University Professor with 10+ years Tutoring Experience
G = ∆H - T ∆S
-187 kJ = -193 kJ - 0.319(∆S)
-187 = -193 - 319∆S
6 = -0.319∆S
∆S = 6/-0.319 = -18.81
Oscar A.
asked 04/04/20A particular reaction has a ΔHo value of -193 kJ and ΔGo of -187 kJ at 319 K. Calculate ΔSo at 319 K in J/K.
The correct answer is -18.81. I am not sure why I keep getting positive 18.81
J.R. S. answered 04/05/20
Ph.D. University Professor with 10+ years Tutoring Experience
G = ∆H - T ∆S
-187 kJ = -193 kJ - 0.319(∆S)
-187 = -193 - 319∆S
6 = -0.319∆S
∆S = 6/-0.319 = -18.81
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