J.R. S. answered 04/04/20
Ph.D. University Professor with 10+ years Tutoring Experience
I'll try to get you started, but there are too many questions for me to answer in one sitting. Maybe I'll come back later and do more.
1)A sample of gas at 4407.73 mmHg inside a steel tank is cooled from 514 degrees C to 8.3 degrees C What is the final pressure of the gas in the steel tank?
P1/T1 = P2/T2 and solving for P2 we have P2 = P1T2/T1 = (4407.73)(281.3K)/787K = 1575 mm Hg (an incredibly high pressure)
2)P1 = 772 torr; T1 = 10 degrees C; P2 = 634.3 torr; T2 = ?
Again, use P1/T1 = P2/T2 and solve for T2: T2 = P2T1/P1 = (634.3)(283K)/772 = 233K -273 = -40ºC
3)A balloon is heated from room temperature (25 degrees C) to 91 degrees Celsius. The internal temperature causes the pressure to rise to 8 atmospheres. What was its initial pressure?
P1 = ?; T1 = 25+273=298K; P2 = 8 atm; T2 = 91+273=364K. Again we can use P1/T1 = P2/T2
P1 = P2T1/T2 = (8)(298)/364 = 6.5 atm = 7 atm
4)The temperature of a sample of gas in a steel tank at 30.0 kPa is increased to 29 ̊C to bring it to a final pressure of 54.5 kPa. What was its initial temperature?
T1 = ?; P1 = 30.0 kPa; T2 = 29+273=302K; P2 = 54.5 kPa. Use P1/T1 = P2/T2 and solve for T1.
T1 = T2P1/P2 = (302)(30.0)/54.5 = 166K - 273 = -107ºC
5)V1= 237mL; T1 = 16°C; V2 = 704 mL ; T2 = ?
Here we can use V1/T1 = V2/T2 and solve for T2
T2 = V2T1/V1 = (704)(289K)/237 = 885K - 273 = 612ºC