J.R. S. answered 04/03/20
Ph.D. University Professor with 10+ years Tutoring Experience
CuO(s) + H2(g) ==> Cu(s) + H2O(g) ... ∆Hrxn = +130.5 kJ
The given ∆H is for the reaction as written, i.e. it is for 1 mole of CuO producing 1 mole Cu. Since 2.0 g Cu is produced, we can find the ∆H for that reaction as well...
2.0 g Cu x 1 mol Cu/63.55 g = 0.0315 moles Cu
0.315 mol Cu x 130.5 kJ/mol Cu = 4.1 kJ for this reaction
Mariah A.
Thank you!04/03/20