Let θ=688∘. Find the reference angle of θ.

Name: Finding Reference Angles
Uploaded: 2020-04-02T20:58:48+00:00
Duration: 2 min 48 s
Description: Answer by Raffi T. to Let θ=688∘. Find the reference angle of θ.

Question

Jon S. · Accepted Answer

Since the circle is 360 degrees, we can first subtract 360 from theta:  688-360 = 328328 degrees is in the 4th quadrant.  In the 4th quadrant the reference angle = 360 -328 = 32 degrees.

Raffi T. · Answer

Let θ=688∘. Find the reference angle of θ.

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Let θ=688∘. Find the reference angle of θ.

2 Answers By Expert Tutors

Still looking for help? Get the right answer, fast.

OR

RELATED TOPICS

RELATED QUESTIONS

tan^2x-sin^2x=tan^2xsin^2x

I need help trying to sole tan^2 x =1 where x is more than or equal to 0 but x is less than or equal to pi

find all solutions to the equation in (0, 2pi) sin(6x)+sin(2x)=0

(2sin18)(cos18)

how do i go about solving a trig identity; that simplify s 1-sin^2 theta/1-cos theta

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