J.R. S. answered 04/02/20
Ph.D. University Professor with 10+ years Tutoring Experience
I'm assuming the change in temperature is 5.19ºC.
q = heat = mC∆T
q = (3.00 g)(4.184 J/g/ºC)(5.19ºC)
q = 65.1 J and this is the heat for 3.00 g. To get J/mole or kJ/mole, we will convert 3.00 g CaCl2 to moles.
3.00 g CaCl2 x 1 mol/111 g = 0.0270 moles
Enthalpy of solution = 65.1 J/0.027 0 mole = 2411 J/mole = 2.41 kJ/mole