The length of a rectangle is 9 times its width. Its area is 81 square meters. What are the dimensions of the rectangle?

Answer 1

In this problem you know the area and the relationship between the length and width.

The area is 81 sqm. The length is 9 times its width.

So let us set A = 81. and L = 9W

The area of a rectangle is length times width A = LW

we know that L = 9W

Substitute and solve by steps:

A = (9W)(W)

81 = (9W)(W)

81 = 9(W)^2 divide by 9

9 = w^2 take sqrt

3 = W and 9W = L 9(3) = L

27 = L

test the result 3 * 27 = 81

Answer 2

l = 9w

A = lw

A = 9w(w) = 9w²

81 = 9w²

9 = w²

w = 3 m

l = 3(9)

l = 27 m

Answer 3