First-degree trigonometric equations help

Question

How do I solve these equations in the interval (0, 360)?

1) 2tanΘ - 3 = 5

2) 4(cscΘ + 2) = cscΘ + 14

3) 2sinΘ + 3 = 3(sinΘ + 1)

Answer 1

1) 2tanΘ - 3 = 5

TanΘ = 4

Θ = Tan^-14 = 76.0º

2) 4(cscΘ + 2) = cscΘ + 14

4CscΘ+8 = CscΘ + 14

3CscΘ = 6

CscΘ = 2 1/SinΘ =2 SinΘ = 1/2Θ

Θ = Sin^-1(1/2) = 30°

3) 2sinΘ + 3 = 3(sinΘ + 1)

2SinΘ + 3 = 3SinΘ + 3

0 = SinΘ

Θ = 0°