J.R. S. answered 04/01/20
Ph.D. University Professor with 10+ years Tutoring Experience
Buffer capacity can be defined as the moles of acid or base needed to change the pH of 1 liter of buffer by 1 pH unit.
In the example given in this problem, apparently buffer E is a basic buffer (such as NH3/NH4+). The reaction is the same in the original buffer as in the diluted buffer, and that is that the added H+ from HNO3 reacts with the base to reduce the concentration of weak base and increase the concentration of the conjugate acid. This can be written as...
B + H+ ==> BH+
wk base.....acid...........conjugate acid
So the more moles of B that you have, the better it can react with H+. So, the original buffer will have more moles /liter than the diluted buffer. This explains why the buffer capacity is greater in the original.
Hope this makes sense.