If we drew a straight line theough the center of the pool touching the outside of the path on both ends, we'd add 4 feet on one end aaaaand 4 feet on the other. The radius is half the diameter.
A = πr2
A = π(102)
A = 314 ft2
Macy M.
asked 03/30/20If we drew a straight line theough the center of the pool touching the outside of the path on both ends, we'd add 4 feet on one end aaaaand 4 feet on the other. The radius is half the diameter.
A = πr2
A = π(102)
A = 314 ft2
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