Formation of aluminum chloride can be described by balanced equation 2Al+3Cl2 2AlCl3

Question

How many moles of Cl2 molecules are required to react with 1.33 mol Al atoms?

Answer 1

2Al + 3Cl₂ ==> 2AlCl₃ ... balanced equation

1.33 moles Al x 3 moles Cl₂/2 moles Al = 1.995 moles Cl₂ = 1.96 moles Cl₂