a) P(M > 73) = P(Z > (73 - 70)/(12/sqrt(36))) = P(Z > 1.5)
b) P(M > 73) = P(Z > (73 - 70)/(12/sqrt(9))) = P(Z > 0.75)
Kirsten C.
asked 03/30/20For a normal population with μ = 70 and σ = 12, find the following.
(a) What is the probability of obtaining a sample mean greater than 73 for a sample of n = 36 scores?
(b) What is the probability of obtaining a sample mean greater than 73 for a sample of n = 9 scores?
a) P(M > 73) = P(Z > (73 - 70)/(12/sqrt(36))) = P(Z > 1.5)
b) P(M > 73) = P(Z > (73 - 70)/(12/sqrt(9))) = P(Z > 0.75)
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