For the following reaction, 5.48 grams of ethylene are mixed with excess hydrogen gas . The reaction yields 5.52 grams of ethane.

Question

For the following reaction, 5.48 grams of ethylene are mixed with excess hydrogen gas . The reaction yields 5.52 grams of ethane.

hydrogen ( g ) + ethylene ( g ) ---> ethane ( g )

What is the theoretical yield of ethane? _____ grams

What is the percent yield for this reaction? ____%

Answer 1

H₂(g) + C₂H₄(g) ===> C₂H₆(g)

hydrogen...ethylene.........ethane....

Theoretical yield of ethane = 5.48 g C₂H₄ x 1 mol/28 g x 1 mol C₂H₆/mol C₂H₄ x 30 g/mol = 5.87 g ethane

Percent yield = actual yield/theoretical yield (x100%) = 5.52 g/5.87 g (x100%)= 94.0% yield