The Ksp of AgCl at 25 C is 1.6*10^-10. Consider a solution that is 1*10^-6 M CaCl2 and 1*10^-5 M AgNO3.

Question

The answer is Q < Ksp and a precipitate will not form.

How do you set up the calculation?

Answer 1

Answer 2

AgCl(s) ==> Ag⁺(aq) + Cl^-(aq)

Q = [Ag⁺][Cl^-]

Since you have 1x10^-6 M CaCl₂, the [Cl^-] = 2x10^-6 M

Since you have 1x10^-5 M AgNO³ , the [Ag⁺] = 1x10^-5 M

Q = (1x10^-5)(2x10^-6) = 2x10^-11

This value of Q is less than the Ksp value of 1.6x10^-10 and so a precipitate will not form n