if a 2.50L sample of air at 24.9 oC is heated until it's volume increases to 3.17, what is the new temperature in oC?

Answer 1

V1 = 2.50 L

T1 = 24.9ºC + 273 = 297.9K

V2 = 3.17 L

T2 = ?

Assuming that the pressure in constant, this deals with Charles' Law

V1/T1 = V2/T2

2.50 L/297.9K = 3.17 L/T2

T2 = (297.9) (3.17)/2.50

T2 = 377.8K

T2 = 377.8 - 273 = 105ºC